SOLUTION: Solve by substitution: y=(5/8)x+4 16y+3x=-40
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Question 1161840
:
Solve by substitution:
y=(5/8)x+4
16y+3x=-40
Answer by
Alan3354(69443)
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y=(5/8)x+4
16y+3x=-40
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Sub for y in the 2nd eqn
=================
Multiply the 1st eqn by 16 to avoid fractions:
16y = 10x + 64
16y + 3x = -40
--
Then sub for 16y in the 2nd eqn