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Question 1161786: Determine the equation of the circle whose center is at (4,5) and tangent to the circle whose equation is x^2 + y^2 + 4x + 6y - 23 = 0
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Determine the equation of the circle whose center is at (4,5) and tangent to the circle whose equation is x^2 + y^2 + 4x + 6y - 23 = 0
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Step 1, find the center (C) and the radius of the circle x^2 + y^2 + 4x + 6y - 23 = 0
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Step 2, find the distance d from (4,5) to C
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Step 3, subtract the radius of the given circle from d ---> the radius of the circle "r"
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Step 4, (x-4)^2 + (y-5)^2 = r^2 is the equation
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