SOLUTION: The line 5x-5y=2 touches the curve x^2y-5x+y+2=0, find the coordinates of the points of intersection. Find the gradient at each of the points
Algebra ->
Finance
-> SOLUTION: The line 5x-5y=2 touches the curve x^2y-5x+y+2=0, find the coordinates of the points of intersection. Find the gradient at each of the points
Log On
Question 1161693: The line 5x-5y=2 touches the curve x^2y-5x+y+2=0, find the coordinates of the points of intersection. Find the gradient at each of the points Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The line 5x-5y=2 touches the curve x^2y-5x+y+2=0, find the coordinates of the points of intersection. Find the gradient at each of the points
-----------
5x-5y=2
Solve for y
y = (5x-2)/5
---
x^2y-5x+y+2=0
Sub for y
----
x^2*(5x-2)/5 - 5x + (5x-2)/5 + 2 = 0
Multiply by 5
x^2*(5x-2) - 25x + (5x-2) + 10 = 0
5x^3 - 2x^2 -20x + 8 = 0
-----
Solve for x
x = 2 is a root
----
x = -2 is a root
---
x = 0.4 is a root
===================
f(x) = 5x^3 - 2x^2 -20x + 8
f'(x) = 15x^2 - 4x - 20
------------
Sub for x at the 3 roots and find the 3 slopes.