SOLUTION: The average number of milligrams (mg) of sodium in a certain brand of low-salt microwave frozen dinners is 660 mg, and the standard deviation is 35 mg. Assume the variable is norma
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-> SOLUTION: The average number of milligrams (mg) of sodium in a certain brand of low-salt microwave frozen dinners is 660 mg, and the standard deviation is 35 mg. Assume the variable is norma
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Question 1161686: The average number of milligrams (mg) of sodium in a certain brand of low-salt microwave frozen dinners is 660 mg, and the standard deviation is 35 mg. Assume the variable is normally distributed.
a. If a single dinner is selected, find the probability that the sodium content will be more than 670 mg.
b. If a sample of 10 dinners is selected, find the probability that the mean of the sample will be larger than 670 mg.
You can put this solution on YOUR website! z=(x-mean)/sd
for a single dinner, z would be (670-660)/35 or 0.29 with probability 0.3875 (using 2/7 for z)
for 10 dinners z=(x bar-mean)/sigma/sqrt(10)
this is z>(2/7)*sqrt(10)=0.9035. That probability is 0.1831
