SOLUTION: Herllo! please help me with this. I am confused. A fence is being built with material 2.8 m in length but there is an existing wall that will be used as one of the boundaries. D

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Question 116166: Herllo! please help me with this. I am confused.
A fence is being built with material 2.8 m in length but there is an existing wall that will be used as one of the boundaries. Draw a diagram and label the demensions of the maximum rectangular area that you can enclosure with
a) 20 pieces
b) 40 pieces

thanks for any help comming this way
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website!
THE MAXIMUM AREA OF A RECTANGLE IS IN THE FORM OF A SQUARE.
SEING AS THERE IS ALREADY ON SIDE YOU NEED TO FIND THREE ADDITIONAL SIDES OF EQUAL LENGTH.
20 PIECES OF 2.8 METERS=56 METERS
56/3=18 2/3 METERS IS THE LENGTH OF EACH OF THE 3 SIDES.
THUS THE ENCLOSED AREA=56/3*3=56 M^2.
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40 PIECES=40*2.8=112 METERS.
112/3=37 1/3 METERS IS THE LENGTH OF EACH OF THE 3 SIDES.
THUS THE ENCLOSED AREA=112/3*3=112 M^2.