SOLUTION: A ship that can cruise at 65 km/h in still waters, set course south-west. It is driven off course by a current flowing W 21° N at a rate of 16 km/h. Calculate the resultant vel

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Question 1161657: A ship that can cruise at 65 km/h in still waters, set course south-west. It is driven off course by a current flowing W 21° N at a rate of 16 km/h.
Calculate the resultant velocity in magnitude and direction

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The way I understand the problem the ship started going south-west in still water, which I would represent like this:

I would decompose the ship-still water velocity vector V
into components in the x- and y-directions:
V%5Bx%5D=-sin%2845%5Eo%29%2A65=-46 and V%5By%5D=-cos%2845%5Eo%29%2A65=-46 .

According to my understanding directions are given as angles measured clockwise from North,
or as acute angles from the North or South directions, with N or S followed by the angle and then the direction.
In the second case, N21%5EoW would mean a direction forming a 21%5Eo angle from North in the direction of West, like this


However, the W21%5EoN in this problem may mean a 21%5Eo angle from West in the direction of North, like this

In that case the x- and y-components of the current vector C are
C%5Bx%5D=-cos%2821%5Eo%29%2A16=-14.9 and C%5By%5D=sin%2821%5Eo%29%2A16=5.7 ,
and the situation would look like this

Then, the components of ship resultant velocity vector red%28R%29 would be
R%5Bx%5D=-46%2B%28-14.9%29=-60.9 and R%5By%5D=-46%2B5.7=-40.3 .
A way to calculate the magnitude of that resultant is using the Pythagorean theorem
R=sqrt%2860.9%5E2%2B40.3%5E2%29=45.7%22km%2Fs%22
The angle alpha if forms with the x-axis is such that
tan%28alpha%29=R%5By%5D%2FR%5Bx%5D=%28-40.3%29%2F%28-60.9%29=0.66174 , which corresponds to alpha=33.5%5Eo
If the current was designated as W21%5EoN
because it was 21%5Eo North from West,
then red%28R%29 is 33.5%5Eo South from West,
and should be called W33.5%5EoS .