SOLUTION: factor fully, 3x^3 - 2x^2-7x - 2 a) (3x+1)(x-7)(x+2) b) (3x-1)(x-2)((x-1) c) (3x-1)(x+2)(x+1) d) (3x+1)(x-2)(x+1)

Algebra ->  Test -> SOLUTION: factor fully, 3x^3 - 2x^2-7x - 2 a) (3x+1)(x-7)(x+2) b) (3x-1)(x-2)((x-1) c) (3x-1)(x+2)(x+1) d) (3x+1)(x-2)(x+1)      Log On


   

Question 1161508: factor fully,
3x^3 - 2x^2-7x - 2
a) (3x+1)(x-7)(x+2)
b) (3x-1)(x-2)((x-1)
c) (3x-1)(x+2)(x+1)
d) (3x+1)(x-2)(x+1)
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E3+-+2x%5E2-7x+-+2+
You can try to regroup to look for a factorization.

You can also try synthetic division for root checking. (Related to using Rational Roots Theorem)

Check for root, -1 for factor x+1, gives quotient 3x^2-5x-2.
Checking that for root,2 for factor x-2, gives quotient 3x+1.

FACTORIZATION: %28x%2B1%29%28x-2%29%283x%2B1%29
FACTORIZATION: highlight%28highlight%28%28x%2B1%29%28x-2%29%283x%2B1%29%29%29
Pick the correct choice. You know the commutative property for multiplication.