SOLUTION: write an equation of the line that passes through ( 6, -5) and is parallel to the line whose equation is 2x-3y=11

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Question 1161493: write an equation of the line that passes through ( 6, -5) and is parallel to the line whose equation is 2x-3y=11
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
the line 2x-3y=11 is the same as 3y=2x-11 and y=(2/3)x-11/3. That slope is 2/3, the coefficient of x.
point slope formula y-y1=m(x-x1), m slope and (x1, y1) point. slope is 2/3 since it is parallel to the above line and parallel lines have same slope
so y+5 (remember sign)(2/3)(x-6)
y+5=(2/3)x-4
y=(2/3)x-9
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%282x%2F3%29-%2811%2F3%29%2C%282x%2F3%29-9%29

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

write an equation of the line that passes through ( 6, -5) and is parallel to the line whose equation is 2x-3y=11