SOLUTION: What is the equation of the line that has a slope of -2 and goes through the point (4, -1)

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Question 1161459: What is the equation of the line that has a slope of -2 and goes through the point (4, -1)
Found 2 solutions by math_helper, greenestamps:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

Start with point-slope form: y-y%5B0%5D+=+m+%28x-x%5B0%5D%29+ where m is slope and
( +x%5B0%5D+, +y%5B0%5D+ ) is any point on the line:
y - (-1) = -2(x - 4)
y + 1 = -2(x - 4) <<<< point-slope form
You can continue, by solving for y, you get slope-intercept form y = mx+b where m is slope and b is the y-intercept:
y + 1 = -2x + 8
y = -2x + 7 <<<< slope-intercept form
Finally, if you can put it in "standard form": Ax + By = C:
2x + y = 7 <<<< standard form (slope is -A/B, y-intercept is C/B,
x-intercept is C/A)

Answer by greenestamps(13196) About Me  (Show Source):
You can put this solution on YOUR website!


You can also use slope-intercept form instead of point-slope form.

With a slope of -2 passing through point (x,y), the equation is

y+=+-2x%2Bb

Plug in the coordinates of the given point to determine the y-intercept b:

-1+=+-2%284%29%2Bb
-1+=+-8%2Bb
b+=+7

The equation is

y+=+-2x%2B7