We diagnalize the matrix:
We find the eigenvalues
λ-7=0; λ+2=0
λ=7; λ=-2
by writing A as
where D is the diagonal matrix with the two eigenvalues on the
main diagonal:
and the matrix S is
where the V's are the two column eigenvectors for the two eigenvalues
We find V1 which is the eigengvector for the eigenvalue λ=7.
We find solutions for
Divide thru by -18
We can take x1=1 and x1=1
So
Now we do the same for the other eigenvalue
---
We find solutions for
Divide thru by -45
We can take x1=1 and x2=1
So
So
And since the determinant of S is 1, to find S-1 we only
need to swap the elements on the the main diagonal and change the
signs of the other two elements"
Then
Edwin