SOLUTION: A soft 100-grams ball A at the velocity of 10 meters per second collides with another 700-grams ball B initially at rest. After collision, the two balls stick together and keep mov

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Question 1161286: A soft 100-grams ball A at the velocity of 10 meters per second collides with another 700-grams ball B initially at rest. After collision, the two balls stick together and keep moving in the same direction as ball A. What is the velocity of the two balls after collision?
A) 12.5 m/s B) - 1.25m/s C) 1.25 m/s D) 125m/s
Answer by ikleyn(52887) About Me  (Show Source):
You can put this solution on YOUR website!
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Apply the Momentum conservation law at collision.


    m%2Av = %28m+%2B+M%29%2AV


m = 0.1 kilograms is the mass of ball A;

v = 10 m/s is its its velocity before colliding;

M = 0.7 kilograms is the mass of ball B;

V is unknown velocity of the merged body.


From the formula,


    V = %28m%2Av%29%2F%28m+%2B+M%29 = %280.1%2A10%29%2F%280.1%2B0.7%29 = 1.25 m/s.    ANSWER

Solved.