SOLUTION: Consider the function
{{{f(x) = sqrt(4-x^2)}}}
Hint: This is the upper half of a circle of radius 2 positioned at (0, 0).
Find the area (in {{{unit^2}}}) between the x-axis a
Algebra ->
Surface-area
-> SOLUTION: Consider the function
{{{f(x) = sqrt(4-x^2)}}}
Hint: This is the upper half of a circle of radius 2 positioned at (0, 0).
Find the area (in {{{unit^2}}}) between the x-axis a
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Question 1161227: Consider the function
Hint: This is the upper half of a circle of radius 2 positioned at (0, 0).
Find the area (in ) between the x-axis and the graph of f over the interval [−2, 2] using rectangles. For the rectangles, use squares 0.8 by 0.8 units, and approximate both above and below the lines.
above: ?
below: ?
Use geometry to find the exact answer (in ).
exact answer: ? Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website!
I drew the half circle in red, and red and green 0.8unit by 0.8unit squares.
Each 0.8unit by 0.8unit square has an area of
The way I see, only the red 0.8 unit by 0.8 unit squares fit inside the half circle.
Their total area is the area approximated below the half circle .
The way I see, to completely cover the half circle, I need to use the red and green squares.
Those are squares.
Their total area is the area approximated above the half circle .
