SOLUTION: The revenue from selling 'q' items is R(q)= 325-q^2, and the total cost is C(q)=50+14q. Write a function that gives the total profit earned, and find the quantity which maximizes t

Algebra ->  Finance -> SOLUTION: The revenue from selling 'q' items is R(q)= 325-q^2, and the total cost is C(q)=50+14q. Write a function that gives the total profit earned, and find the quantity which maximizes t      Log On


   



Question 1161198: The revenue from selling 'q' items is R(q)= 325-q^2, and the total cost is C(q)=50+14q. Write a function that gives the total profit earned, and find the quantity which maximizes the profit.
Profit pi(q)=?
Quantity maximizing profit q=?

Found 2 solutions by solver91311, ikleyn:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




Find and set it equal to zero. Solve for


John

My calculator said it, I believe it, that settles it


Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
The revenue from selling 'q' items is R(q)= 325-q^2, and the total cost is C(q)=50+14q.
Write a function that gives the total profit earned, and find the quantity which maximizes the profit.
Profit pi(q)=?
Quantity maximizing profit q=?
~~~~~~~~~~~~~~~~~~~~~


The given "revenue function" R(q) = 325 - q^2 of the number "q" of sold items is monotonically DECREASING function,
according to the posted formula.


But it NEVER may happen that the revenue function be a DECREASING function of the number of sold items.


It is for the first time in my life I see such an absurdist statement.

Imagine: you sell something, and the amount of money in your pocket is decreasing . . .


It may happen only if the seller pays exra from his pocket to a buyer for every "sold" item . . .


         Who created this nonsense ?


O my god, it goes under the section "Finance" . . .

It looks like the author is studying Finance . . .

Good luck then . . .


Thank you for making me laugh . . .