SOLUTION: how many different 3 digit no divisible by 5 can be formed using the elements (1,2,3,4,5,)

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Question 1161153: how many different 3 digit no divisible by 5 can be formed using the elements (1,2,3,4,5,)
Found 3 solutions by Alan3354, solver91311, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
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how many different 3 digit no divisible by 5 can be formed using the elements (1,2,3,4,5,)
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If you mean not divisible by 5:
The units digit is 1 of 4.
The other 2 are 1 of 5 (if repeats are allowed, not specified)
5*5*4 = 100

Answer by solver91311(24713) About Me  (Show Source):
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You didn't say repetition is not allowed, so I'll assume that it is.

There are five ways to choose the first digit, five ways to choose the second digit, and four ways to choose the last digit because the last digit cannot be 5. So:




John

My calculator said it, I believe it, that settles it

Answer by Edwin McCravy(20065) About Me  (Show Source):
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Assuming that you can only use a digit once.

Choose the 3rd digit 4 ways (not 5)
Choose the 1st digit 4 ways
Choose the 2nd digit 3 ways

4∙4∙3 = 48 ways

 1.  123
 2.  124
 3.  132
 4.  134
 5.  142
 6.  143
 7.  152
 8.  153
 9.  154
10.  213
11.  214
12.  231
13.  234
14.  241
15.  243
16.  251
17.  253
18.  254
19.  312
20.  314
21.  321
22.  324
23.  341
24.  342
25.  351
26.  352
27.  354
28.  412
29.  413
30.  421
31.  423
32.  431
33.  432
34.  451
35.  452
36.  453
37.  512
38.  513
39.  514
40.  521
41.  523
42.  524
43.  531
44.  532
45.  534
46.  541
47.  542
48.  543

Edwin