SOLUTION: A six-person committee must be formed from a group of 6 boys and 7 girls.
a) Determine the probability there is an equal number of boys and girls.
I attempted this question
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a) Determine the probability there is an equal number of boys and girls.
I attempted this question
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Question 1161143: A six-person committee must be formed from a group of 6 boys and 7 girls.
a) Determine the probability there is an equal number of boys and girls.
I attempted this question and got 700/ 1716 or about 41%.
b) Determine the probility there is at most 2 boys on the committee.
Thank you in advance for any help:) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Total ways to choose 6 from 13 is 13C6, so that is the denominator.
numerator is 6 so 6C3*7C3=700, as you wrote
at most two boys.
0 boys and that numerator is 7C6 or 7
1 boy and that numerator Is 7C5*6C1=126
2 boys and it is 7C4*6C2=35*15=525
That sum is 658
the probability is 658/1716-0.3834