SOLUTION: The smallest of 6 consecutive integers is p, and the greatest is q. What is the value of the average of p and q in terms of p?

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Question 1161101: The smallest of 6 consecutive integers is p, and the greatest is q. What is the value of the average of p and q in terms of p?
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
The smallest of 6 consecutive integers is p, and the greatest is q. What is the value of the average of p and q in terms of p?
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If the smallest number is  p,  then the greatest is   q = p+5.   Therefore,


    the value of the average of p and q in terms of p is  %28p+%2B+%28p%2B5%29%29%2F2 = %282p%2B5%29%2F2 = p + 2.5.     ANSWER



CHECK.  Let p = 1;  then q = 6  and the average of the two numbers is  %281%2B6%29%2F2 = 7%2F2 = 3.5 = 1 + 2.5.    ! Correct !

Solved.

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The solution and the answer by @josgarithmetic both are   W R O N G,

since he calculated   TOTALLY  DIFFERENT  average - not which was requested.

Therefore,  IGNORE  his post,  for your safety.


Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
p, p+1, p+2, p+3, p+4, p+5


average, %28cross%286p%2B%286-1%29%29%2F6%29
cross%28%286p%2B5%29%2F6%29


Average of p and p+5:
%28p%2Bp%2B5%29%2F2
highlight%28%282p%2B5%29%2F2%29