A man cycles to a place at 10km per hour and arrives at 1 pm. If he cycles at 15km per hour he arrives
at the same place at 11 am. What speed must he cycle to arrive at noon ?
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Let d be the distance to travel.
Then from the condition, you have this "time" equation
-
= 2 hours.
To solve this equation, multiply both sides by 30. You will get
3d - 2d = 60,
d = 60.
Thus the distance is 60 kilometers.
At the rate of 15 km/h, the cyclist cover it in 4 hours and arrives at 11 am.
To arrive at noon, the cyclist shoud travel 5 hours; hence, his speed should be 60/5 = 12 kilometers per hour. ANSWER
Solved.