SOLUTION: PQRS is a parallelogram whose two vertices are P(1,2) and R(6,4).PS is parallel to the line L1 which cuts Y-axis at 5and passes through (-2,3).
a) Find the equation of line PS.
b
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-> SOLUTION: PQRS is a parallelogram whose two vertices are P(1,2) and R(6,4).PS is parallel to the line L1 which cuts Y-axis at 5and passes through (-2,3).
a) Find the equation of line PS.
b
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Question 1160870: PQRS is a parallelogram whose two vertices are P(1,2) and R(6,4).PS is parallel to the line L1 which cuts Y-axis at 5and passes through (-2,3).
a) Find the equation of line PS.
b) Find the coordinates of S.
c) Find the coordinates of Q.
d) Find the equation of line L2 which is the perpendicular bisector of line QR. Answer by solver91311(24713) (Show Source):
Since "cuts the -axis at 5", one of the points on the line is . The other is given as . Knowing two points on a line allows you to compute the slope of the line:
You can do your own arithmetic.
Given that is parallel to , we know that the line containing must have the same slope as . And, since the line containing must perforce pass through point , we can write the equation of the line containing using the Point-Slope form of an equation of a line.
And you can simplify as needed.
But now you have a problem because the other three parts of your question cannot be answered specifically without additional information. Point S could be anywhere on the line containing with the exception of at point P itself. You don't even specify if the vertices are labeled alphabetically clockwise or counterclockwise, so you can't tell whether or .
See diagram:
John
My calculator said it, I believe it, that settles it
