SOLUTION: The sum of two consecutive integers is -173. Find the least of the two integers. and The sum of three times a number and 21 is 28. Find the number.

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Question 1160783: The sum of two consecutive integers is -173. Find the least of the two integers.
and
The sum of three times a number and 21 is 28. Find the number.

Found 3 solutions by josgarithmetic, saw, Alan3354:
Answer by josgarithmetic(39630)   (Show Source):
You can put this solution on YOUR website!
(What's the trouble?)

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Answer by saw(34)   (Show Source):
You can put this solution on YOUR website!
Solution.
The sum of two consecutive integers is -173.
1st integer = x
2nd integer = x+1
x+(x+1) = -173
Remove parentheses
x+x+1 = -173
Collect the like terms
2x+1 = -173
Move constant to the right side and change its sign
2x = -173-1
Calculate the difference
2x = -174
Divide both sides of the equation by 2
x = -87
x+x+1 = -173
Use substitution to find the integers
-87+(-87+1) = -173
-87+-86 = -173
So two consecutive integers is -87 and -86.
The sum of three times a number and 21 is 28.
1st integer = 3x
2nd integer = 21
3x+21 = 28
Move constant to the right side and change its sign
3x = 28-21
Calculate the difference
3x = 7
3x+21 = 28
Use substitution to find the integers
7+21 = 28
So the integers is 7 and 21.

Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
The sum of two consecutive integers is -173. Find the least of the two integers.
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-173/2 = -86.5
---> -87 and -86
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No need for a Master's Thesis
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The sum of three times a number and 21 is 28. Find the number.
n = the number
3n + 21 = 28
3n = 7
n = 7/3