SOLUTION: At an evening showing of the movie "Divine Secrets of the Ya-Ya Sisterhood", there were 42 more women than men in attendance. If there were 90 people in the theater, how many were

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: At an evening showing of the movie "Divine Secrets of the Ya-Ya Sisterhood", there were 42 more women than men in attendance. If there were 90 people in the theater, how many were       Log On


   

Question 1160782: At an evening showing of the movie "Divine Secrets of the Ya-Ya Sisterhood", there were 42 more women than men in attendance. If there were 90 people in the theater, how many were women?
Found 3 solutions by ikleyn, josgarithmetic, saw:
Answer by ikleyn(52848) About Me  (Show Source):
You can put this solution on YOUR website!
.

   W - M = 42

   W + M = 90

--------------------------Add the equations, and you will learn quickly on

                          how many woman were in the theater.


Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x-y=42%2Cx%2By=90%29

Add the two equations and divide by 2.

Answer by saw(34) About Me  (Show Source):
You can put this solution on YOUR website!
Solution.
Let x = men
Let x+42 = women
x+(x+42) = 90
Remove parentheses
x+x+42 = 90
Collect the like terms
2x+42 = 90
Move constant to the right side of the equation and change its sign
2x = 90-42
Calculate the difference
2x = 48
Divide both sides by 2
x = 24
x+42
Use substitution
24+42 = 66
So the men were 24 and women were 66.
Check-----
x+(x+42) = 90