SOLUTION: The length of a rectangle is 8 feet longer than it’s wide. If each side is increased 8 feet, then the area is multiplied by 3. What is the size of the original rectangle?
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: The length of a rectangle is 8 feet longer than it’s wide. If each side is increased 8 feet, then the area is multiplied by 3. What is the size of the original rectangle?
Log On
Question 1160592: The length of a rectangle is 8 feet longer than it’s wide. If each side is increased 8 feet, then the area is multiplied by 3. What is the size of the original rectangle? Found 2 solutions by Boreal, Alan3354:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Area1=x(x+8)=x^2+8x, where x= width and x+8= length
Area 2=(x+8)(x+16)=x^2+24x+128=3x^2+24x
2x^2=128
x=8 feet
original rectangle is 8 x16 feet with area 128 ft^2.
new rectangle is 16*24 feet with area 384 ft^2.
You can put this solution on YOUR website! The length of a rectangle is 8 feet longer than it’s wide. If each side is increased 8 feet, then the area is multiplied by 3. What is the size of the original rectangle?
----------------
L*W = A (original area)
W*(W+8) = A
---
(W+8)*(W+16) = 3*W*(W+8)
W+16 = 3W
W = 8 ft
L = 16 ft
=====================
Orig area = 128 sq feet
---
Increased area = 16*24 = 384 sq ft
