SOLUTION: Find an equation of the circle with center at the origin which passes through the point P(5,-3)

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Question 1160508: Find an equation of the circle with center at the origin which passes through the point P(5,-3)

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

an equation of the circle is:
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 where h and k are coordinates of the center, and r is a radius
given:
the circle with center at the origin, means h=0 and k=0
so far your equation is
%28x-0%29%5E2%2B%28y-0%29%5E2=r%5E2
x%5E2%2By%5E2=r%5E2.....use given: circle passes through the point P(5,-3) to calculate r%5E2
5%5E2%2B%28-3%29%5E2=r%5E2
25%2B9=r%5E2
34=r%5E2
and your equation is
x%5E2%2By%5E2=34







Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Find an equation of the circle with center at the origin which passes through the point P(5,-3)
Equation of a circle: matrix%281%2C3%2C+%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2%2C+%22=%22%2C+r%5E2%29
matrix%281%2C3%2C+%285+-+0%29%5E2+%2B+%28-+3+-+0%29%5E2%2C+%22=%22%2C+r%5E2%29 ------ Substituting (0, 0) for (h, k), and (5, - 3) for (x, y)

Equation of THIS circle: highlight_green%28matrix%281%2C3%2C+x%5E2+%2B+y%5E2%2C+%22=%22%2C+34%29%29