SOLUTION: From two tracking stations 435 km apart, a satellite is sighted at C above AB, making CAB = 48.3° and ZCBA = 62.6°. Find the height of the satellite, to the nearest tenth of a ki

Algebra ->  Triangles -> SOLUTION: From two tracking stations 435 km apart, a satellite is sighted at C above AB, making CAB = 48.3° and ZCBA = 62.6°. Find the height of the satellite, to the nearest tenth of a ki      Log On


   

Question 1160334: From two tracking stations 435 km apart, a satellite is sighted at C above AB, making CAB = 48.3° and ZCBA = 62.6°. Find the height of the satellite, to the nearest tenth of a kilometre.

Answer by Alan3354(69443) About Me  (Show Source):
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From two tracking stations 435 km apart, a satellite is sighted at C above AB, making CAB = 48.3° and ZCBA = 62.6°. Find the height of the satellite, to the nearest tenth of a kilometre.
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a is side opposite CAB (CAB is angle A)
etc.
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If it's between A and B:
The 3rd angle is 180 - (A+B) = 69.1 degs
Find either side a or b using the Law of Sines.
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To find side a:
a/sin(48.3) = c/sin(69.1) = 435/sin(69.1)
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Then, h = a*sin(62.6)