SOLUTION: A container with base measuring 60cm by 40cm and a height of 25cm was 4/5 filled with water. some of the water was removed, causing the water level to fall by 5 cm. The remaining w

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Question 1160279: A container with base measuring 60cm by 40cm and a height of 25cm was 4/5 filled with water. some of the water was removed, causing the water level to fall by 5 cm. The remaining water was then poured in to a tank and a basin, filling them to their brims, the capacity of basin was 1/3 that of the tank. if the tank was 18cm long and 15 cm wide. what was the height of the water in the tank??
Answer by greenestamps(13206) About Me  (Show Source):
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Depth of container: 25cm

Depth of water in container originally: (4/5) of 25cm = 20cm

Depth of water after some was removed: 20-5 = 15cm

Volume of water remaining: 60*40*15 = 36000 cm^3

Capacity of tank: (3/4) of 36000 cm^3 = 27000 cm^3 (because the capacities of the tank and basin are in the ratio 3:1)

Height of tank (volume of tank, divided by cross-sectional area of the tank): 27000/(18*15) = 27000/270 = 100

ANSWER: the height of the water in the tank = the height of the tank = 100cm.