SOLUTION: A developer wants to enclose a retangular grassy lot that borders a city street for parking. If the developer has 336 feet of fencing and does not fence the side along the street,

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Question 116024: A developer wants to enclose a retangular grassy lot that borders a city street for parking. If the developer has 336 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed? Please help me figure out how to come up with this answer.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x=width, so 336-2x=length ___ area=(x)(336-2x)=336x-2x^2

this is the graph of a parabola and the maximum lies on the axis of symmetry

equation for axis of symmetry is x=-b/2a ___ x=-336/((2)(-2))

solve for x and then find area