Question 1160177: a car losses by 20%,18 % and 15% of its value at the begining ofthe first , second and third year respectively.if the car cost 180000 find its value
Found 2 solutions by Theo, MathTherapy:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the value of the car is 180,000 when it is bought.
at the end of the first year, it's value drops by 20% to be equal to 180,000 - .2 * 180,000 = 144,000
a the end of the second year, it's value drops by an additional 18% to be equal to 144,000 - .18 * 144,000 = 118,080.
at the end of the third year, it's value drops by an additional 15% to be equal to 118,080 - .15 * 118,080 = 100,368.
it's value at the end of the third year is 100,368.
if you just use the value factors, you would get the value factor at the end of 3 years is 1 * (1 - .2) * (1 - .18) * (1 - .15) = 1 * .8 * .82 * .85 = .5576.
.5576 * 180,000 = 100,368 which is the value of the car at the end of the third year.
Answer by MathTherapy(10556)  (Show Source):
You can put this solution on YOUR website!
a car losses by 20%,18 % and 15% of its value at the begining ofthe first , second and third year respectively.if the car cost 180000 find its value
A loss of 20% means that it's then worth 80% (.8) of its original value
A loss of 18% means that it's then worth 82% (.82) of its original value
A loss of 15% means that it's then worth 85% (.85) of its original value
Therefore, value at end of 3 years: 
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