SOLUTION: There are 46 runners in a race, and no ties. Suppose you wanted to calculate how many ways can the first three finishers be chosen from the 46 runners, regardless of how they are a

Algebra ->  Probability-and-statistics -> SOLUTION: There are 46 runners in a race, and no ties. Suppose you wanted to calculate how many ways can the first three finishers be chosen from the 46 runners, regardless of how they are a      Log On


   

Question 1160157: There are 46 runners in a race, and no ties. Suppose you wanted to calculate how many ways can the first three finishers be chosen from the 46 runners, regardless of how they are arranged. Would you use a combination or a permutation?
Answer by ikleyn(52792) About Me  (Show Source):
You can put this solution on YOUR website!
.

Combinations.  Chose 3 of 46  by C%5B46%5D%5E3 ways.

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On Combinations and Permutations,  see introductory lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Simple and simplest problems on permutations
    - Special type permutations problems
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations

    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.