SOLUTION: In a certain fraction, the numerator is 7 less than the denominator. If booth the numerator and denominator are increased by 2, the new fraction equals 4/11. What is the original f
Question 1160140: In a certain fraction, the numerator is 7 less than the denominator. If booth the numerator and denominator are increased by 2, the new fraction equals 4/11. What is the original fraction? Found 4 solutions by MowMow, josgarithmetic, MathTherapy, ikleyn:Answer by MowMow(42) (Show Source):
You can put this solution on YOUR website! N/D = (D-7)/D
(D-7+2) = (D-5)/(D+2)
2D=73
D = 73/2 which is not a whole number
Therefore, there is no solution.
You can put this solution on YOUR website! In a certain fraction, the numerator is 7 less than the denominator. If booth the numerator and denominator are increased by 2, the new fraction equals 4/11. What is the original fraction?
I don't know why he/she came to the conclusion that there's no INTEGER value for the denominator.
The fraction you're looking for is:
Very SIMPLE!! From resulting fraction, , SIMPLY subtract 2 from numerator and also denominator. Doesn't that give you
@MowMow, it is clear from your post, that you are not able to solve simplest algebra problems correctly,
and are not able even read and interpret their condition in a right way.
I observed your contribution to the forum,
and with 179% confidence I can say that you have no necessary knowledge to be a Math tutor.