SOLUTION: Use Gauss-Jordan method to find the row canonical form of the matrix 1 -2 3 1 2 1 1 4 -1 3 2 5 9 -2 8

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Question 1160071: Use Gauss-Jordan method to find the row canonical form of the matrix
1 -2 3 1 2
1 1 4 -1 3
2 5 9 -2 8

Found 2 solutions by Edwin McCravy, AnlytcPhil:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

-1R1+1R2->R2:
matrix%283%2C1%2C-1%2C1%2C%22%22%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
-2R1+1R2->R3:
matrix%283%2C1%2C-2%2C%22%22%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
-3R2+1R3->R3:
matrix%283%2C1%2C%22%22%2C-3%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
2R2+3R1->R1:
matrix%283%2C1%2C3%2C2%2C%22%22%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
1R3+1R2->R2
matrix%283%2C1%2C%22%22%2C1%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
1R3+2R1->R1
matrix%283%2C1%2C2%2C%22%22%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
(1/6)R1->R1
(1/3)R2->R2
(1/2)R2->R3
matrix%283%2C1%2C%221%2F6%22%2C%221%2F3%22%2C%221%2F2%22%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29 <-- answer
Edwin

Answer by AnlytcPhil(1807) About Me  (Show Source):
You can put this solution on YOUR website!


-1R1+1R2->R2:
matrix%283%2C1%2C-1%2C1%2C%22%22%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
-2R1+1R2->R3:
matrix%283%2C1%2C-2%2C%22%22%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
-3R2+1R3->R3:
matrix%283%2C1%2C%22%22%2C-3%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
2R2+3R1->R1:
matrix%283%2C1%2C3%2C2%2C%22%22%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
1R3+1R2->R2
matrix%283%2C1%2C%22%22%2C1%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
1R3+2R1->R1
matrix%283%2C1%2C2%2C%22%22%2C1%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29
(1/6)R1->R1
(1/3)R2->R2
(1/2)R2->R3
matrix%283%2C1%2C%221%2F6%22%2C%221%2F3%22%2C%221%2F2%22%29matrix%283%2C1%2C%22%22%2C%22%22=%22%22%2C%22%22%29 <-- answer
Edwin