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Question 1160053: Find the EXACT VALUE of the following, A) (SIN 30°)²+cot60+(csc45)² B) (csc60)/sin45° *for letter B, it is (csc60) over sin45°
Found 3 solutions by MowMow, MathTherapy, ikleyn:
Answer by MowMow(42)   (Show Source):
You can put this solution on YOUR website! A) (SIN 30°)²+cot60+(csc45)² = (.5)^2 + .5774 + 1.414^2 = .25+.577+2 = 2.8274
cot60 = 1/Tan60
csc45 = 1/Sin45
B) (csc60)/sin45° = (1/Sin60)/Sin45 = 1.1547/.7071 = 1.633
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
Find the EXACT VALUE of the following, A) (SIN 30°)²+cot60+(csc45)² B) (csc60)/sin45° *for letter B, it is (csc60) over sin45°
If you don't know by now, that person DIDN'T give you EXACT values.
Answer by ikleyn(52812)  (Show Source):
You can put this solution on YOUR website! .
@MowMow, it is clear from your post, that you don't know basics of Trigonometry.
I observed your contribution to the forum,
and with 179% confidence I can say that you have no necessary knowledge to be a Math tutor.
I ask you STOP posting to this forum.
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