SOLUTION: An interior angle of a regular polygon is 160 degress. Find the sum of it's interior angles.

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Question 1159975: An interior angle of a regular polygon is 160 degress. Find the sum of it's interior angles.
Found 3 solutions by MowMow, ikleyn, Alan3354:
Answer by MowMow(42) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of all the degrees of the interior angles equals (n - 2)x180.
Then 160N = 180(N-2)
160N = 180N - 360
20N = 360
n = 18 sides
18x160 = 2880 degrees

Answer by ikleyn(52749) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let "n" be the number of sides (= vertices).


Then

    n*160 = (n-2)*180  degrees

    160n  = 180n - 360

    360   = 180n - 160n

    360   = 20n

       n  = 360%2F20 = 18.


The sum of all interior angles = (18-2)*180 = 16*180 = 2880 degrees.    ANSWER

Solved.



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
An interior angle of a regular polygon is 160 degress. Find the sum of it's interior angles.
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Ext angles = 180 - 160 = 20 degs
360/20 = 18 sides.
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Sum = 180*(18-2) = 2880 degs
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PS it's = it is