SOLUTION: 2. If point P lies on the unit circle with coordinates (1/2,-sqrt3/2) , then find all six trigonometric ratios. sin P = ____-Sqrt(3)/2___________ (1/2 pt) csc P = ____2/Sqrt(3)

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Question 1159752: 2. If point P lies on the unit circle with coordinates (1/2,-sqrt3/2) , then find all six trigonometric ratios.
sin P = ____-Sqrt(3)/2___________ (1/2 pt) csc P = ____2/Sqrt(3)___________ (1 pt)
cos P = _____1/2__________ (1/2 pt) sec P = _____2__________ (1 pt)
tan P = _______-Sqrt(3)________ (1 pt) cot P = ______-1/Sqrt(3)_________ (1 pt)
Found 2 solutions by MowMow, Alan3354:
Answer by MowMow(42) (Show Source):
You can put this solution on YOUR website!
2. If point P lies on the unit circle with coordinates (1/2,-sqrt3/2) , then find all six trigonometric ratios.
sin P = ____-Sqrt(3)/2___________ (1/2 pt) csc P = ___-_2/Sqrt(3)___________ (1 pt)
cos P = _____1/2__________ (1/2 pt) sec P = _____2__________ (1 pt)
tan P = _______-Sqrt(3)________ (1 pt) cot P = ______-1/Sqrt(3)_________

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Difficult to interpret.
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The underscores ___________ are of no use.

SOLUTION: 2. If point P lies on the unit circle with coordinates (1/2,-sqrt3/2) , then find all six trigonometric ratios. sin P = ____-Sqrt(3)/2___________ (1/2 pt) csc P = ____2/Sqrt(3)_

SOLUTION: 2. If point P lies on the unit circle with coordinates (1/2,-sqrt3/2) , then find all six trigonometric ratios. sin P = -Sqrt(3)/2___ (1/2 pt) csc P = 2/Sqrt(3)_