SOLUTION: Suppose the annual consumption of chicken mean is 20.84 pounds per person, and the standard deviation for the consumption of chicken per person is 9.193 pounds. The mean weight of

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Question 1159739: Suppose the annual consumption of chicken mean is 20.84 pounds per person, and the standard deviation for the consumption of chicken per person is 9.193 pounds. The mean weight of chicken consumed for a sample of 200 randomly selected people is one value of many that form the sampling distribution of sample means.
a) What is the value for this sampling distribution?
b) What is the standard deviation of this sampling distribution?
Answer by Boreal(15235) (Show Source):
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The mean of the sampling distribution is the same mean of 20.84
the sd is the sd of the population/sqrt(n)=9.193/sqrt(200)=0.6500 or 0.65
This means that if multiple samples of 200 people are taken, they will cluster around the mean of 20.84 pounds and have a sd of 0.65 pounds