SOLUTION: A jar contains 8 pennies, 2 nickels and 3 dimes. A child selects 2 coins at random without replacement from the jar. Let X represent the amount in cents of the selected coins.
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-> SOLUTION: A jar contains 8 pennies, 2 nickels and 3 dimes. A child selects 2 coins at random without replacement from the jar. Let X represent the amount in cents of the selected coins.
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Question 1159687: A jar contains 8 pennies, 2 nickels and 3 dimes. A child selects 2 coins at random without replacement from the jar. Let X represent the amount in cents of the selected coins.
Find the probability X = 10
Find the probability X = 11 Answer by Edwin McCravy(20060) (Show Source):
The only way to get 10 cents with 2 coins is to select the two nickels.
That's one way out of C(13,2) = (13∙12)/(2∙1) = 78
Probability = 1/78
The only way to get 11 cents with 2 coins is to select one of the 3 dimes and one of the 8 pennies.
That's C(3,1)∙C(8,1) = 3∙8 = 24
or 24 ways out of the 78 or 24/78 which reduces to 4/13.
Edwin
