Question 1159670: Let U = {q, r, s, t, u, v, w, x, y, z}; A = {q, s, u, w, y}; B ={q, s, y, z}; C = {v, w, x, y, z} List the members of the indicated set, using set braces.
A' ∪ B
Found 2 solutions by MathLover1, jim_thompson5910:
Answer by MathLover1(20850)   (Show Source):
You can put this solution on YOUR website!
Let U = {q, r, s, t, u, v, w, x, y, z}
A = {q, s, u, w, y}
B ={q, s, y, z}
C = {v, w, x, y, z}
List the members of the indicated set, using set braces.
A' ∪ B
A' => all elements in U that are not in A
A' ={ r, t, v, x, z}
A' ∪ B=>all elements in A' or in B
A' ∪ B={ q, s, r, t, v, x,y, z}
Answer by jim_thompson5910(35256)  (Show Source):
You can put this solution on YOUR website!
Start with the universal set U
U = {q, r, s, t, u, v, w, x, y, z}
Cross off anything you find in set A = {q, s, u, w, y}
U = {q, r, s, t, u, v, w, x, y, z}
U \ A = {q, r, s, t, u, v, w, x, y, z} blue items are crossed off the list
U \ A = {r, t, v, x z}
A ' = {r, t, v, x, z}
The notation U \ A tells the reader to "start with set U and kick out the items in set A", which is what a complement set is. We write A', or A prime, to indicate a complement set to set A.
Then union this with the items in set B.
A' U B = {r, t, v, x, z} U {q, s, y, z}
A' U B = {r, t, v, x, z, q, s, y, z}
A' U B = {q, r, s, t, v, x, y, z}
Notice I sorted alphabetically and tossed out the duplicates
The union of two sets is the result of combining the two sets together. Almost like we're dumping the two smaller sets A' and B into one larger bin.
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