SOLUTION: Find the amplitude, the period, and the phase shift. y = 5 sin(3x − π/2) I got 5 for amplitude, 2pi/3 for period, and 3pi/2 for phase shift. The amplitude and period are rig

Algebra ->  Trigonometry-basics -> SOLUTION: Find the amplitude, the period, and the phase shift. y = 5 sin(3x − π/2) I got 5 for amplitude, 2pi/3 for period, and 3pi/2 for phase shift. The amplitude and period are rig      Log On


   

Question 1159663: Find the amplitude, the period, and the phase shift.
y = 5 sin(3x − π/2)
I got 5 for amplitude, 2pi/3 for period, and 3pi/2 for phase shift. The amplitude and period are right but phase shift is wrong, why??
Found 3 solutions by math_helper, MathLover1, MathTherapy:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
phase shift = +-%28%28pi%2F2%29%29%2F3+=+-pi%2F6+. Because it is -pi%2F6 it LAGS the unshifted +5sin%283x%29+


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Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

y+=+Asin%28Bx-C%29
in your case
B=3 and C=pi%2F2
phase shift: C%2FB=%28pi%2F2%29%2F3=pi%2F6

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the amplitude, the period, and the phase shift.
y = 5 sin(3x − π/2)
I got 5 for amplitude, 2pi/3 for period, and 3pi/2 for phase shift. The amplitude and period are right but phase shift is wrong, why??
A HORIZONTAL/PHASE SHIFT is calculated as: abs%28c%2Fb%29. With c being -+pi%2F2 and b being 3 (coefficient of "x"), abs%28c%2Fb%29 becomes: 

ACCEPT NO other answer, especially the one that claims that it's pi%2F6- She's ALMOST ALWAYS WRONG!!