Question 1159456: A father is 25 years older than his son. In 10 years, he will be twice as old as his son.
Find their present ages. Answer by ikleyn(52787) (Show Source):
Let x be the age of the son; then the father's age is (x+25), according to the condition.
In 10 years, the son's age will be (x+10), while the father's age will be (x+25+10) = x+35.
The condition says that
2*(x+10) = x+35.
Simplify and solve
2x + 20 = x + 35
x = 35 - 20 = 15.
ANSWER. The son is 15 years old; the father is 15+25 = 40 years old.
