SOLUTION: Determine all the values where sinx=√3 cosx for 0^0 ≤x ≤360°

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Question 1159351: Determine all the values where sinx=√3 cosx for 0^0 ≤x ≤360°
Found 2 solutions by greenestamps, MowMow:
Answer by greenestamps(13216) About Me  (Show Source):
You can put this solution on YOUR website!


sin%28x%29+=+sqrt%283%29%2Acos%28x%29
sin%28x%29%2Fcos%28x%29+=+tan%28x%29+=+sqrt%283%29

For what angles between 0 and 360 degrees is the tangent equal to the square root of 3?

(This is basic; you should know it. Think of the 30-60-90 right triangle....)

Answer by MowMow(42) About Me  (Show Source):
You can put this solution on YOUR website!
sin(x)=√3cos(x) for 0^0 ≤x ≤360°
Simplify to Sin(x)/Cos(x) = Tan(x) = √3
Then arcTan = √3, x = 60 and 240 degrees
There are two intersections (x,y)= (60°,√3) and (240°,√3)
Tangent is positive in the 1st and 4th quadrant which this shows.