Question 1159330: In how many ways can you select a set of 3 letters from JasmineOrtz
if the order of selection matters? In how many ways can you select a set of 3 letters if the order of selection does not matter? Thank you for your help I have been watching videos but I haven't been able to solve it
Answer by ikleyn(52802) (Show Source):
You can put this solution on YOUR website! In how many ways can you select a set of 3 letters from JasmineOrtz if the order of selection matters?
In how many ways can you select a set of 3 letters if the order of selection does not matter?
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(a) The word "JasmineOrtz" has 11 letters, and they all are different.
So, when the order of selection does matter, you may
- put any of 11 letters in the first position, when you select; (it gives you 11 options)
- put any other of remaining 10 letter in the second position ((it gives you 10 options)
- put any other of remaining 9 letter in the second position ((it gives you 9 options)
.
Therefore, you have 11*10*9 = 990 options (permutation) in all, in this case.
(b) If the order does not matter, you should divide this number of 990 by 6,
because any set of 3 letters has 3! = 1*2*3 = 6 permutations.
So, the answer in this case is 990/6 = 165.
Solved.
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To get elementary, basic knowledge on permutations, see these introductory lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Simple and simplest problems on permutations
- Special type permutations problems
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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