SOLUTION: (x-3)^2 +(y-2)^2=16 find the equation of the tangent line at the point (-2,1)
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Question 1159059
:
(x-3)^2 +(y-2)^2=16 find the equation of the tangent line at the point (-2,1)
Found 2 solutions by
greenestamps, MathLover1
:
Answer by
greenestamps(13200)
(
Show Source
):
You can
put this solution on YOUR website!
The given point is not on the given curve....
Answer by
MathLover1(20850)
(
Show Source
):
You can
put this solution on YOUR website!
The given point (
,
) is not on the given curve.
check:
