SOLUTION: Brad and Gary threw countless water balloons at each other. But even though they were only 50 feet apart, none hit. Now the two boys are charging each other with squirt guns. If

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Brad and Gary threw countless water balloons at each other. But even though they were only 50 feet apart, none hit. Now the two boys are charging each other with squirt guns. If      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1158914: Brad and Gary threw countless water balloons at each other. But even though they were only 50 feet apart, none hit. Now the two boys are charging each other with squirt guns. If Brad runs at 4.5 feet per second and Gary runs at 5.5 feet per second, and neither one trips, how many seconds will it be before they're face to face?
Found 2 solutions by hudikamo, ikleyn:
Answer by hudikamo(4) About Me  (Show Source):
You can put this solution on YOUR website!
Time : Brad : Gary
0 : 0 : 50
1 : 4.5 : 44.5
2 : 9 : 39
3 : 13.5 : 33.5
4 : 18 : 28
5 : 22.5 : 22.5
Both meet at the 5th second.

Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
.

This problem was posted to the forum long time ago.

I solved it under this link

https://www.algebra.com/algebra/homework/Length-and-distance/Length-and-distance.faq.question.1159050.html