SOLUTION: Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of C. Carry your intermediate computations to at least four decimal

Algebra ->  Probability-and-statistics -> SOLUTION: Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of C. Carry your intermediate computations to at least four decimal       Log On


   

Question 1158879: Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of C.
Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.
P (Z < C) = 0.8389
Value of C?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
you have p(z < c) = .8389
that represents the area to the left of the z-score.
using the online z-score calculator that can be found at , the z-score is equal to .99.
this is what it looks like on that calculator.

$$$

you are using the value from an area portion of the calculator and looking for the area to the left of the z-score.
the area to the left of the z-score is the area that is below the z-score.