SOLUTION: Find the exponential equation whose graph passes through the points (-1, 1/2 ) and (2,32) y=

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Question 1158834: Find the exponential equation whose graph passes through the points (-1, 1/2 ) and (2,32)
y=
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+a%2Ab%5Ex......use the point (-1,+1%2F2 )
1%2F2+=+a%2Ab%5E-1
1%2F2+=+a%2Fb
b=2a..........eq.1


32+=+a%2A%282a%29%5E2.....using the point (2,32)
32=+a%2A4a%5E2
32=4a%5E3
8=a%5E3
a=root%283%2C8%29
a=root%283%2C2%5E3%29
a=+2.........eq.2

substitute in eq.1
b=2a..........eq.1
b=2%2A2
b=4


your equation is:
y+=++2%2A4%5Ex