SOLUTION: John and Sam have a lawn mowing service. At one home, John can mow the lawn by himself in 2 hours, but it takes Sam 2.5 hours. How many hours t will it take them to mow the same la

Algebra ->  Rate-of-work-word-problems -> SOLUTION: John and Sam have a lawn mowing service. At one home, John can mow the lawn by himself in 2 hours, but it takes Sam 2.5 hours. How many hours t will it take them to mow the same la      Log On


   



Question 1158819: John and Sam have a lawn mowing service. At one home, John can mow the lawn by himself in 2 hours, but it takes Sam 2.5 hours. How many hours t will it take them to mow the same lawn together?.
Answer by ikleyn(52767) About Me  (Show Source):
You can put this solution on YOUR website!
.

Working alone, John makes  1%2F2 = 0.5  of the job per hour


Working alone, Sam  makes  1%2F2.5 = 2%2F5 = 0.4 of the job per hour.


Working together, they make  0.5 + 0.4 = 0.9  of the job per hour.


It means that they complete the job in  1%2F0.9 hours = 11%2F9 hours = 1 hour, 6 minutes and 40 seconds.   ANSWER

Solved.

------------------------------

It is a standard and typical joint work problem.

There is a wide variety of similar solved joint-work problems with detailed explanations in this site.  See introductory lessons
    - Using Fractions to solve word problems on joint work
    - Solving more complicated word problems on joint work
    - Selected joint-work word problems from the archive


Read them and get be trained in solving joint-work problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic
"Rate of work and joint work problems"  of the section  "Word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.