SOLUTION: Test the indicated claim about the means of two populations and find confidence interval. A researcher was interested in comparing the amount of time (in hours) spent watching t

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Question 1158784: Test the indicated claim about the means of two populations and find confidence interval.
A researcher was interested in comparing the amount of time (in hours) spent watching television by women and by men. Independent simple random samples of 14 women and 17 men were selected, and each person was asked how many hours he or she had watched television during the previous week. The summary statistics are as follows.
Women
x1=12.5 hr.
s1=3.9 hr.
n1=14.
Men
x2=13.8 hr.
s2=5.2 hr.
n2=17.
Use a 0.05 significance level to test the claim that the mean amount of time spent watching television by women is smaller than the mean amount of time spent watching television by men.
1) Null and Alternative Hypothesis
2) Calculator work
3) Test Statistics and P-Value
4) Conclusion about the null hypothesis
5) Final conclusion that addresses the original claim
6) Test the claim by constructing a confidence interval
7) Confidence interval conclusion
Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website!
Ho. mu women= or > mu men.
Ha: mu women < mu men
alpha=0.05 P{reject Ho|Ho true}
Test statistic is a t 0.95 df=29
critical value is t< -1.699
Input these into calculator for 2 sample Test.
The test statistic is a t with a value of -0.795 df calc is 28..8 (df=29 if done by hand)
p-value is 0.2167
fail to reject Ho and insufficient evidence to conclude that there is a difference between the two groups.
CI should contain 0 for the difference between the two groups.
95% CI is (-18.56, 15.96) for the difference. This contains 0, so the CI is consistent with no difference between the two groups.