Question 1158639: Set-Builder Notation and Interval Notation.
Suppose A={x is an element of real number: -2 less than or equal to X < 5 } and B= (-1, 6]
1. Find A U B and give the answer in interval notation. (7marks)
2. Write A n (intersection) B as one set using set builder notation (4marks)
Answer by KMST(5396)   (Show Source):
You can put this solution on YOUR website! Set A includes the number -2, and all the real numbers between -2 and 5, but not the number 5.
We could say that  .
1. Find A U B and give the answer in interval notation.
The set A U B is the union of sets A and B,
so it contains all the real number that belong to A, or B.
That would include all the numbers in [-2,5) because they belong to set A.
A U B would also include [5,6] because those real numbers belong to set B.
A U B =  because all the numbers in [-2,6] belong to either A, or B, or both and no other number.
2. Write A n (intersection) B as one set using set builder notation
A (intersection) B included all the numbers that belong to both sets A and B, and no other number.
All the numbers between -1 and 5, not including -1 or 5, belong to A and belong to B, and therefore belong to the intersection of A and B.
Those numbers, and no other numbers satisfy  .
In set builder notation, that would be {x|x is a real number and -1
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