SOLUTION: Refer to the contingency table shown below.
Smoking by Race for Males Aged 18-24
Smoker
(S) Nonsmoker
(N) Row Total
White(W) 290 560 850
Black(B) 30
Algebra ->
Probability-and-statistics
-> SOLUTION: Refer to the contingency table shown below.
Smoking by Race for Males Aged 18-24
Smoker
(S) Nonsmoker
(N) Row Total
White(W) 290 560 850
Black(B) 30
Log On
S = smoker
N = nonsmoker
W = white male aged 18-24
B = black male aged 18-24
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Part i.
P(S) = probability of selecting a smoker
P(S) = (number of smokers)/(number total)
P(S) = 320/1000
P(S) = 0.3200
Answer: 0.3200
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Part ii.
P(W) = probability of selecting a white male
P(W) = (number of white males)/(number total)
P(W) = 850/1000
P(W) = 0.8500
Answer: 0.8500
Nice work on getting parts i and ii correct.
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Part iii.
P(S|W) = probability of selecting a smoker (S) given they are white male (W)
P(S|W) = (number of white male smokers)/(number of white males)
P(S|W) = 290/850
P(S|W) = 0.341176471 which is approximate
P(S|W) = 0.3412 rounded to four decimal places
notice how we only focus on the white male row since we are given the person is a white male.
Answer: 0.3412
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Part iv.
This time we focus on the black male row. Ignore everything else.
There are 30 who smoke out of 150 total
P(S|B) = probability of selecting a smoker (S) given they are a black male (B)
P(S|B) = 30/150
P(S|B) = 0.2000
Answer: 0.2000
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Part v.
This time we consider all males surveyed since we don't have a conditional probability.
P(S and W) = probability of selecting a smoker and a white male
P(S and W) = (number of smokers who are white)/(number of people total)
P(S and W) = 290/1000
P(S and W) = 0.2900
Answer: 0.2900
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Part vi.
P(N and B) = probability of selecting a nonsmoker and a black male
P(N and B) = (number of nonsmokers who are black)/(number of people total)
P(N and B) = 30/1000
P(N and B) = 0.0300