SOLUTION: how many mL of 50% dextrose solution and how many mL of water are needed to prepare 100 mL of 15 % dextrose solution?

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Question 1158396: how many mL of 50% dextrose solution and how many mL of water are needed to prepare 100 mL of 15 % dextrose solution?
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


(1) A standard algebraic solution....

x mL of the 50% dextrose, plus (100-x) mL of water (0% dextrose), equals 15% of 100 mL:

.50%28x%29%2B0%28100-x%29+=+.15%28100%29
.5x+=+15
x+=+15%2F.5+=+30
ANSWER: 30 mL of 50%; 70 mL of water

(2) Basically the same solution, informally....

The water is 0% dextrose, so all of the dextrose comes from the 50% dextrose solution.
In the final mixture, the amount of dextrose is 15% of 100 mL, or 15 mL.
The 50% dextrose solution is one-half dextrose; to get 15mL of dextrose, you need 30 mL of solution.

(3) A completely different method of solving....

You are mixing 0% and 50% dextrose to get 15% dextrose.
15% is 15/50 = 3/10 of the way from 0% to 50%.
So 3/10 of the mixture is the 50% dextrose.
3/10 of 100 mL is 30 mL.


Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x for volume of 50% dextrose

50x=15%2A100
x=%2815%2A100%29%2F50
x=30

30 ml. of 50% dextrose
70 ml. water