SOLUTION: When ax³ + bx² + cx - 4 is divided by (x+2), the remainder is double that obtained when the expression is divided by (x+1). Show that c can have any value and find b in terms of
Algebra ->
Test
-> SOLUTION: When ax³ + bx² + cx - 4 is divided by (x+2), the remainder is double that obtained when the expression is divided by (x+1). Show that c can have any value and find b in terms of
Log On
Question 1157973: When ax³ + bx² + cx - 4 is divided by (x+2), the remainder is double that obtained when the expression is divided by (x+1). Show that c can have any value and find b in terms of a. Answer by KMST(5377) (Show Source):
You can put this solution on YOUR website!
If you divide by , you obtain a quotient and remainder that is a constant.
You may remember that in then
If you did not remember, you would understand that if the reminder is ,
it means that and that
for , .
So --> .
Similarly the remainder, when dividing by is --> .
Then, -->-->-->-->
