SOLUTION: The perimeter of a triangle is 75 inches. One side of a triangle is 10 inches more than the second side. The third side is 5 inches more than twice the second side. Find 5he measur

Algebra ->  Triangles -> SOLUTION: The perimeter of a triangle is 75 inches. One side of a triangle is 10 inches more than the second side. The third side is 5 inches more than twice the second side. Find 5he measur      Log On


   

Question 1157964: The perimeter of a triangle is 75 inches. One side of a triangle is 10 inches more than the second side. The third side is 5 inches more than twice the second side. Find 5he measure of each side
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a triangle is 75 inches. One side of a triangle is 10 inches more than the second side. The third side is 5 inches more than twice the second side. Find 5he measure of each side
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The sides are a, b & c
a is the shortest side.
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b = a+10
c = 2b + 5 ---> c = 2*(a+10) + 5
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a + b + c = 75
---
a + a+10 + 2a+25 = 75
etc

Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.

If you attentively read the problem, you will see that the equation is


    a + (a+10) + (2a+5) = 75,


giving the answers  a= 15 for the shortest side, a+10 = 25 for the middle side and 2*15+5 = 35 for the longest side.

Solved.